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Parametrization of a line isgamma(t)=u+tvwhere u is apoint on the line and v is a vector parallel to the limeGiven two points P=(3,5) and varphi=(13,7)If we want to parametrize the straight line passing through (3,5) and (13,7)we can take u=$(3,5)and v=(:3,5:)-(:13,7:)=(:-10,-2:)so parametrization of a line is{:[" can we write "gamma(t)=(:3","5:)+t(:-10","-2:)],[x(t)=3-10 t],[y(t)=5-2t]:}(a) pi_(1)quad3x-y-4z=0Comparing vec(gamma) vec(n)_(1)=dvec(n)_(1)≐3 hat(ı)- hat(ȷ)-4 hat(k)whichix normal vector at bar(A) । plare?{:[pi2quad x+y+z=1],[=>quad ... See the full answer