Question Solved1 Answer Part A For the two vectors in the figure (Figure 1) , find the magnitude of the vector product A⃗ ×B⃗ . Part B Find the direction of the vector product A⃗ ×B⃗ . Find the direction of the vector product . +z-direction

DJ7MCW The Asker · Physics

Part A

For the two vectors in the figure (Figure 1) , find the magnitude of the vector product A⃗ ×B⃗ .

Part B

Find the direction of the vector product A⃗ ×B⃗ .

Find the direction of the vector product .

  +z-direction or
 

-z-direction

Part C

Find the magnitude of B⃗ ×A⃗ .

Part D

Find the direction of B⃗ ×A⃗ .

+z-direction  or -z-direction

 

 

 

 

Transcribed Image Text: Part A For the two vectors in the figure (Figure 1) , find the magnitude of the vector product A⃗ ×B⃗ . Part B Find the direction of the vector product A⃗ ×B⃗ . Find the direction of the vector product . +z-direction
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Transcribed Image Text: Part A For the two vectors in the figure (Figure 1) , find the magnitude of the vector product A⃗ ×B⃗ . Part B Find the direction of the vector product A⃗ ×B⃗ . Find the direction of the vector product . +z-direction
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Part A:{:[ vec(A)xx vec(B)=(2.80[cos 60 hat(x)+sin 60 hat(y)])xx(1.90[cos 60 hat(x)-sin 60 hat(y)])],[=-2.80 xx1.90 cos 60 sin 60 hat(z)-2.80 xx1.90 cos 60 sin 60 hat(z)],[=-2xx2.80 xx1.90 cos 60 sin 60 hat(z)],[=-4.61cm^(2) hat(z)],[" Magnitude " ... See the full answer