(a) Mass of mixture = mass of 2n0+ mass of HCe Mass of HCl= Molar mass (HCl)xxn_(0) of moles. Molarity of HCe solution =1.00M Volume =50.0ml.{:[" No. o moles "=" Molarity "xx" Volume "(l)],[=(1.00 xx phi phi)/(100 phi)=(1)/(20)" moles "=0.05" moles "]:}{:[" Mass of "HCl=36.46 xx0.05=],[:." Mass of mixture "=(1.82+0.962)=],[Q=m xx C xx Delta T],[Q=0.962 xx4.184 xx(25.4-21.0)],[Q=-14.49J]:}-ve sign shows heat released.(c){:[DeltaH_(gamma xx n)=(Q)/(n_(z_(n)0))=(-14.49)/(0.012)=-1207.5J//mol=-1.207],[kJ//mor],[n=" no. of moles of "2n0=(" given mass ")/(" molar mass ")=0.962],[" no. of moles of "2" moles "=n=0.012 ... See the full answer