Question Solved1 Answer Problem 2. (20 pts) A closed surface with dimensions a = b =0.300 m and e=0.500 m is located as in the figure below. The left edge of the closed surface is located at position x=a. The electric field throughout the region is non-uniform and given by E-(2.0+ 3.0x){N/C, where x is in meters. Calculate the net electric flux leaving the closed surface. What net charge is enclosed by the surface?

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Transcribed Image Text: Problem 2. (20 pts) A closed surface with dimensions a = b =0.300 m and e=0.500 m is located as in the figure below. The left edge of the closed surface is located at position x=a. The electric field throughout the region is non-uniform and given by E-(2.0+ 3.0x){N/C, where x is in meters. Calculate the net electric flux leaving the closed surface. What net charge is enclosed by the surface?
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Transcribed Image Text: Problem 2. (20 pts) A closed surface with dimensions a = b =0.300 m and e=0.500 m is located as in the figure below. The left edge of the closed surface is located at position x=a. The electric field throughout the region is non-uniform and given by E-(2.0+ 3.0x){N/C, where x is in meters. Calculate the net electric flux leaving the closed surface. What net charge is enclosed by the surface?
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Solution rarrElectric field at the Left end alAnd the eleesic field at the right end af the closed surface =E_(2){:[E_(2)=[2.0+3.0(0.800)^(2)] hat(i)N//C],[=3.92 hat(i)N//C]:}Area of the Left and righ sarfaces{: ... See the full answer