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let y(t) be the amount of Salt af ary tinie t:.(dy)/(dt)= (rete of Sat flowing into tenk) -(vete of Salt out of tank)(dy^('))/(dt)=(3(kg)//urxx4inim//wi^('))-((y)/(v(t))*1" wirf/in ")Hene V(t)= ehaying velune of Solution{:[v(t)=50+(4-1)t],[v(t)=" So "+3t quad A+0" verflow "quad" So "+3t=74],[3t=74-50],[" overflow at "t=8" min "]:}:.(dy)/(dt)=12-(y)/((50+3t))ov (dy)/(dt)+(y)/(50+3t)=12 rarr1 let mu(t)=e^(int(1)/((50+3t))dt)Mutiply eqn (c) on b/s by mu(t){:[root(3)(50+3t)(dy)/(dt)+(y(t))/(sqrt(3t+50)(50+3t))=12root(3)(50+3t)],[root(3)(50+3t)(dy)/(dt)+(y(t))/((50+3t)^(2//3))=12^(3)sqrt(50+3t)]:}Apply reverse product nuee f(dg)/(dt)+g(df)/(dt)=(d)/(dt)fga ... See the full answer