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Sol Foom fundemental Flitection Equetion\frac{d t}{d v}=k v+cAP K=\frac{\mu P Q}{\triangle P A^{2}} \quad C=\frac{\mu \cdot R_{m}}{A D P}At Conslent \Delta p.\begin{array}{l}d t=k v d v+c d v \\t=\frac{k v^{2}}{2}+c v \\\frac{t}{v}=\frac{k v}{2}+c\end{array}Plot b / w \quad \frac{t}{v} vs v gues slope =\frac{k}{2} \& intercept =Con plotting y=1.6711 x+0.166 \quad \therefore \quad R^{2}=01.\begin{aligned}\frac{K}{2} & =1.6711 \quad C=0.166 \\K & =3.3422 \\\frac{\mu \alpha P}{\Delta P A^{2}} & =3.3422 \\\frac{\mu \alpha P}{A^{2}} & =33.4022 \quad \frac{M R m}{A}=16.6 .\end{aligned}(1) for \Delta p= soup.\frac{\mu \alpha P}{\Delta P A^{2}}=6.6844 \quad \frac{\mu R_{m}}{A \Delta P}=0.332 : t=\frac{6.6844}{2} v^{2}+0.332 Vfor V=0.1 \mathrm{~m}^{3}\begin{array}{l}t=0.03342+0.0332 \\t=0.06662 \mathrm{sec}=3.99 \mathrm{~min}\end{array}(2) At stete of Filtectiv V=0\begin{array}{l}\frac{d t}{d v}=K=\begin{array}{c}6.6844+0.332=0.332 \\(0)\end{array} q_{0}=\frac{d v}{d t}=\frac{1}{0.332}=\frac{1}{3.012}\end{array}At end. V=0.1 \mathrm{~m}^{3}\begin{array}{l}\text { At end } \\\frac{d t}{d v}=(6.6844) \times(0.1) \neq 0.332=1 . \\\frac{d v}{d t}=1 \mathrm{~m}^{3} / \mathrm{s}\end{array}Cleoly Rate Decreoscs wilh time Beceuse Rifaction Cove shesisbne invere as pilterto Procecds.(3)\begin{array}{l}=2 \cdot 5 / \mathrm{m}^{3} \\\end{array}Time t=\frac{V}{q}=\frac{0.1}{\frac{1}{2}}=0.2 \mathrm{sec} using given data and variables we can find the requied parameters for any doubts write in comments ...