please answer 1-3. will upvote

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(1) \Rightarrow solutiont.Let ((p \rightarrow q) \wedge(q \rightarrow \varepsilon)) \rightarrow(p \rightarrow \varepsilon)=A.Truth table for given statement is,From the last column all values of given statement dre TEMe.\therefore Civen statement is Tautology.(2) Let ((p \vee q) \vee \varepsilon) \leftrightarrow(p \vee(q \vee \varepsilon))=B.Truth table for given statement is,Feom the last column, all values of given sfectement are TEue.Henle given statement is Tautology(3) Let(\neg q \wedge(p \rightarrow q)) \leftrightarrow \neg p=cFrom the teuth table, value of given statement are true as well as farse. (feom last column).\therefore Given statement neither tautology noz a contradiction. ...