# Question Solved1 AnswerQuestion 13 1 pts What is the pH of a solution obtained by mixing 119.44 mL of 0.50 M CH3NH2 and 121.33 mL of 1.0 MCH3NH3CI? (K (CH3NH2) = 5.2 x 10-4) Input your answer to 2 decimal places. For example, if your answer is pH = 12, enter 12.00 10.7

Transcribed Image Text: Question 13 1 pts What is the pH of a solution obtained by mixing 119.44 mL of 0.50 M CH3NH2 and 121.33 mL of 1.0 MCH3NH3CI? (K (CH3NH2) = 5.2 x 10-4) Input your answer to 2 decimal places. For example, if your answer is pH = 12, enter 12.00 10.7
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Transcribed Image Text: Question 13 1 pts What is the pH of a solution obtained by mixing 119.44 mL of 0.50 M CH3NH2 and 121.33 mL of 1.0 MCH3NH3CI? (K (CH3NH2) = 5.2 x 10-4) Input your answer to 2 decimal places. For example, if your answer is pH = 12, enter 12.00 10.7
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Moles of{:[CH_(3)NH_(2)=(0.50 xx119.44)/(1000)],[=0.05972],[CH_(3)NH_(3)^(+)Cl^(-)=(121.33 xx1)/(1000)],[=0.12133]:}Given,{:[k_(b)" of "CH_(3)NH_(2)=5.2 xx10^(-4)],[:.pk_(b)=-log(5.2 xx ... See the full answer