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/Question 18 (1 point) Patients arrive randomly at an eye care clinic for eye exam. Suppose that there is only one optometrist. The time required for the exam varies from patient to patient. Arrival rates have been found to follow the Poisson distribution (i.e., exponentially distributed inter-arrival times), and the service times follow the exponential distribution. The average arrival rate is 12 patients per hour, and the average service rate is 15 patients per hour. Patients stay in the waiting room until the optometrist is ready to see them. How many patients, on the average, will be in the waiting room? 1 patient 0.8 patients 4 patients 3.2 patients

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Question 18 (1 point) Patients arrive randomly at an eye care clinic for eye exam. Suppose that there is only one optometrist. The time required for the exam varies from patient to patient. Arrival rates have been found to follow the Poisson distribution (i.e., exponentially distributed inter-arrival times), and the service times follow the exponential distribution. The average arrival rate is 12 patients per hour, and the average service rate is 15 patients per hour. Patients stay in the waiting room until the optometrist is ready to see them. How many patients, on the average, will be in the waiting room? 1 patient 0.8 patients 4 patients 3.2 patients

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Transcribed Image Text: Question 18 (1 point) Patients arrive randomly at an eye care clinic for eye exam. Suppose that there is only one optometrist. The time required for the exam varies from patient to patient. Arrival rates have been found to follow the Poisson distribution (i.e., exponentially distributed inter-arrival times), and the service times follow the exponential distribution. The average arrival rate is 12 patients per hour, and the average service rate is 15 patients per hour. Patients stay in the waiting room until the optometrist is ready to see them. How many patients, on the average, will be in the waiting room? 1 patient 0.8 patients 4 patients 3.2 patients

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Transcribed Image Text: Question 18 (1 point) Patients arrive randomly at an eye care clinic for eye exam. Suppose that there is only one optometrist. The time required for the exam varies from patient to patient. Arrival rates have been found to follow the Poisson distribution (i.e., exponentially distributed inter-arrival times), and the service times follow the exponential distribution. The average arrival rate is 12 patients per hour, and the average service rate is 15 patients per hour. Patients stay in the waiting room until the optometrist is ready to see them. How many patients, on the average, will be in the waiting room? 1 patient 0.8 patients 4 patients 3.2 patients

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UNITS IN QUEUE(LQ) = ARRIVAL TIME^2 / (SERVICE RATE * (SERVICERATE - ARRIVAL RATE)) = 12^2 / (15 * ... See the full answer