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SolutionGiven,(1)mean mu=60Standard deviation x=15By using Gmpioical Rule,=>68% of data fall withn one stondard deviation 95% of date fall withon two standare deriation 99.7% of data fall within three standard deviation.a){:[P(45 < x < 75)=P((45-60)/(15) < (x-mu)/(pi) < (75-60)/(15))],[= ... See the full answer