strength and material pls show how you solve it in detail

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\begin{array}{l}P=\text { pressune }=9.25 \mathrm{Mpa} \\\sigma y=190 \mathrm{Mpa} \\F_{05}=2.5 \\\sigma_{n}=\text { hoop stress }=\frac{P D}{2 t}=\sigma_{1} \\\sigma_{C}=\text { anial shes }=\frac{P D}{4 t}=\sigma_{2} \\\sigma_{3}=0 \\2_{\text {max }}=\frac{\sigma_{1}-\sigma_{3}}{2}=\frac{P D}{4 t}\end{array}By tresca criterion\begin{array}{c}\eta_{\max } \leq \frac{\sigma y}{2 F O 5} \quad \Rightarrow \frac{P D}{4 t} \leq \frac{190}{2 \times 2.5} \\\Rightarrow \frac{9.25}{4} \frac{D}{t} \leq \frac{190}{5} \\\frac{D}{t} \leq 16.43 \quad \text { answer }\end{array} ...