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Answr 5.1: Step  1 : seperate half reaction  MnO4- -->  MnO2 N2H4 -->N2  Now we will balance oxygen by adding water as N an Mn are balanced  MnO4- -->  MnO2  + 2H2O N2H4 -->N2  Now we will balance hydrogen by adding proton MnO4- +4H+ -->  MnO2  + 2H2O N2H4 -->N2  +4H+ Balance the charge with electon MnO4- +4H+ + 3e---->  MnO2  + 2H2O N2H4 -->N2  +4H+ + 4e-  multiplying rection by  4 to first an 3 to secon reacton  4MnO4- +16H+ + 12e---->  4Mn ... See the full answer