Question Question No. 5 The 50-lb wheel has a radius of gyration about its center of gravity Gof kg = 0.7 ft. If it rolls without slipping, determine its angular velocity when it has rotated clockwise 90° from the position shown. The spring AB has a stiffness k = 1.20 lb/ft and an unstretched length of 0.5 ft. The wheel is released from rest. 3 ft 0.5 ft + 0.5 ft иии, k = 1.20 lb/ft 1 ft

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Transcribed Image Text: Question No. 5 The 50-lb wheel has a radius of gyration about its center of gravity Gof kg = 0.7 ft. If it rolls without slipping, determine its angular velocity when it has rotated clockwise 90° from the position shown. The spring AB has a stiffness k = 1.20 lb/ft and an unstretched length of 0.5 ft. The wheel is released from rest. 3 ft 0.5 ft + 0.5 ft иии, k = 1.20 lb/ft 1 ft
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Transcribed Image Text: Question No. 5 The 50-lb wheel has a radius of gyration about its center of gravity Gof kg = 0.7 ft. If it rolls without slipping, determine its angular velocity when it has rotated clockwise 90° from the position shown. The spring AB has a stiffness k = 1.20 lb/ft and an unstretched length of 0.5 ft. The wheel is released from rest. 3 ft 0.5 ft + 0.5 ft иии, k = 1.20 lb/ft 1 ft
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Solution is attached in the image Posted below. Hope it helps. If you have any query please comment in the comment box. 506 wheel.Radius ob Gyration Ka_(1)=0.7ft stibbness AB=1.200//Ft unstretched length:- 0.5ft# Now we have Initial wheel & spring condition.Initial _(" stretch ")=> stretched lengthunstretched length=>3.04138-0.5=>2.54138final spring condition when B aligns with the fixture poutIt took (1" th ")/(4) Revolution to reach B {:[" l.e "=(" Circumference by ")/(4)],[=>(pi D)/(4)=>(pi r)/(2)=(pi xx1)/(2)]:}r=1ft[ Radis of wheel ]# Initial potential energ y :{:[P_(i)=(1)/(2) ... See the full answer