Question Solved1 Answer ineed very fast answer in 20 min Quiz 1: Water at a flow rate of 0.1 kg/s is to be heated from 10 to 25 °C. A heat pump unit operating on the ideal vapor compression cycle and using R-134a is utilized to heat the water. Knowing that the evaporator temperature is 0 °C, the condenser temperature is 40 °C, and the value of Cp for water is 4.18 kJ/kg.K, determine the COP of the heat pump and amount of energy saved by using the heat pump instead of directly heating water using an electric heater.

A reheat cycle with two stages of reheating is executed with steam expanding initially from 200 bar (20 Mpaa) and 540 deg C. The 2 reheater pressures are 40 bar (4 Mpaa) and 10 bar (1 Mpaa) and the steam leaves each reheater at 540 deg C. Steam is bled in between two reheating sessions at a pressure equal to 20 and 15 bars into 2 open feedwater heaters. Condensation occurs at 60 deg C. All expansion and compression efficiencies are 93 %. There is a total of 4.5+ (3*SN/100) kg/sec of steam circulated in the cycle. *Note that SN=11* IMPORTANT Note : Make a summary of your answers. You may fill up this page or maybe handwritten per item number A reheat cycle with two stages of reheating is executed with steam expanding initially from 200 bar (20 Mpaa) and 540 deg C. The 2 reheater pressures are 40 bar (4 Mpaa) and 10 bar (1 Mpaa) and the steam leaves each reheater at 540 deg C. Steam is bled in between two reheating sessions at a pressure equal to 20 and 15 bars into 2 open feedwater heaters. Condensation occurs at 60 deg C. All expansion and compression efficiencies are 93 %. There is a total of 4.5+ (3*SN/100) kg/sec of steam circulated in the cycle. Answer the following: fill up the blanks in the items below: 1. Equipment layout and TS diagram for the cycle 2. Actual mass of steam bled into the open heater m1'= _kg/kg for the heater nearest to the SGU/boiler and m2 = _kg/sec for the heater nearest to the condenser. 3. Actual turbine work in KW Answer: 4. Energy Chargeable (actual) Answer: 5. Ideal Rankine engine efficiency % Answer: 6. Actual Rankine cycle efficiency % Answer: 7. If the generator efficiency = 95%, brake engine efficiency = 90% what is the plant capacity in MW? Answer: 8. If Cp water = 4.187 KJ/kg-K; cooling water enters the condenser at 10 deg C and leaves at 21 deg C, find amount of cooling water needed by the condenser in kg/sec. (ACTUAL) Answer: 9. Combined Heat Rate in KJ/KW-hr Answer: 10. Speed of the turbine shaft in rev per minute if Torque measured by the dynamometer= 5.92 KN-m. Answer:

I was wondering if someone can help explain how these equations are working together in order to solve the problem here below. An infinite slab of charge of thickness 22. lies in the xy-plane between z = -2, and z = +20. The volume charge density is a constant. E zo 2z 0 2z - 2. z>2. z<z (a) Use Gauss's Law to find an expression for the electric field strength inside the slab. Use a Gaussian pillbox inside the slab to determine the electric field strength inside. In this case: -2, <zzo Use Gauss's Law and add up the electric flux from each portion of the surface. P= £.dĀ= Ē.dĀ+ S + · dÃ+ S E dĀ = qene - + + = bottom top curved The electric field will always be parallel to the sides of the curved surface. The pillbox will only contain the charge it encloses. The enclosed charge will need to be put in terms of the charge density. The electric field is constant on each surface and always parallel to the area vector. (b) Find an expression for the electric field strength above the slab. Now all the possible charge is contained in the pillbox up to Zo, so the enclosed charge becomes: Yenc = PV = p(22,A) Same reasoning in part (a) applied here. (C) Draw a graph of E from z = 0 to z = 3 Z. Use the equations found in parts (a) and (b) and apply to their respective ranges.

Find an autonomous differential equation with all of the following properties: equilibrium solutions at y = 0 and y = 5, • y' > 0 for 0 < y< 5, and • y' < 0 for - <y<0 and 5 <y< 0.

5.76 ft 5.76 ft 5.76 ft 5.76 ft Determine the force in member DE and in each of the members located to the left of DE for the inverted Howe roof truss shown. State whether each member is in tension or compression. 400 lb 600 lb 800 lb А 600 lb 400 lb D 6.72 ft -Oos H E -10.54 ft 12.5 ft

Listed below are yearly forecasts of “free cash flow” (operating cash flow plus investment-related cash flow) for Bomkat LLC. Year Cash Flow 2018 -$2.0 million. 2019 -$1.2 million. 2020 -$0.4 million. 2021 $0.2 million. 2022 $0.7 million. 2023 $1.1 million. After year 2023, cash flows are anticipated to grow by 2% per year, in perpetuity. For simplicity, assume all that cash flows occur at the end of each year. Assume a discount rate of 8% per year. (a) What is the value as of the end of 2023 of all Bomkat’s cash flows to be received after 2023? (b) What is the value of Bomkat LLC as of the end of 2017?

Background An important element in a lawsuit is “discovery” where the parties are required to share with each other documents relevant to the dispute. Excluded from such disclosure obligation are documents in which a claim of solicitor-client privilege are claimed. In a lawsuit, the Office of the Information and Privacy Commissioner of Alberta (OIPC) ordered the production of records over which the University of Calgary had claimed solicitor-client privilege. The University provided a list of documents indicating solicitor-client privilege had been asserted over the records. The OIPC issued a Notice to Produce Records under s. 56(3) of the Freedom of Information and Protection of Privacy Act which requires a public body must produce required records to the Commissioner “[d]espite . . . any privilege of the law of evidence”. The University disputed the release of the privileged documents. Question Please advise what the Supreme Court of Canada decided about S. 56(3) of the Freedom of Information and Protection of Privacy Act and whether it applied to the privileged documents.