【General guidance】The answer provided below has been developed in a clear step by step manner.Step1/3To calculate the pH at various points in the titration, we need to determine the number of moles of propanoic acid that have reacted with the NaOH. We can do this using the balanced chemical equation for the reaction:C3H5COOH + NaOH -> C3H5COO- Na+ + H2Omoles of NaOH added = 0.100 M x volume of NaOH added= 0.100 M x 50.0 mL= 0.00500 moles NaOHmoles of propanoic acid reacted = 0.200 M x 50.0 mL - 0.00500 moles NaOH= 0.00950 moles propanoic acidWe can use an ICE table to calculate the pH at each point in the titration:i) Before any NaOH is added (0% completion):Initial: 0.200 M propanoic acid, 0.000 M NaOHChange: -x, +x, +xEquilibrium: 0.200-x M propanoic acid, x M propanoate ion, x M NaOHK_a = 1.3 x 10^-5pH = pK_a + log([propanoate ion]/[propanoic acid])pH = 4.87 + log(0/0.200)pH = 4.87Explanation: ... See the full answer