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The potentiat energy (U) of atomic bonding can be expreseed ar- v=-(A)/(gamma^(m))+(B)/(gamma^(n))=-(A)/(gamma^(2))+(B)/(gamma10) m=2,n=10,r_(0)=4xx10^(-10)mThe force between the afoms at an intercatomic distance ro ir-f=-(dU)/(dr)=-(2A)/(gamma^(3))+(10 B)/(r 11)At equillibrium diatance r_(0),f=0, Therefore, (2) giver -(2A)/(gamma_(0)3)+(10 B)/(gamma_(0)11)=0or, A=(5B)/(r_(0)^(8))=(5B)/((4xx10^(-10))^(8))=7.63 xx10^(75)B Or, A=7.63 xx10^(75)BThe dissociation energy or bond energy, U_(0), is the energy reeleased durung bond formatlonUsing eq n^(n) (2) and pulting r=r_(0); i.e,U_(0)=-(A)/(r_(0)^(2))+(B)/(r_(0)^(10))=-(A)/(r_(0)^(2))(1-(B)/(Ar_(0)^(8)))Pulting A=(5B)/(gamma_(0)8),{:[U_(0)=-((A)/(r_(0)^(2)))(1-(1)/(5))=-((4)/(5))(A)/(gamma_(0)^(2))],[" Now, "{:[U_(0)=-5exx],[=-5xx1.6 xx10^(-19)J],[:.A=(5)/(4)(4xx10^(-10))^(2)(5xx1.6 xx10^(-19))],[A=1.6 xx10^(-37)Jm^(2)]:}],[" From eg "(n)/((3))]: ... See the full answer