Practice Exercise 2.3 only. Thankyou

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Topic:Page NoSof{:[F_(1)=4N," Fast "],[F_(2)=6N," North Eart "],[F_(3)=8N," south. "]:}Resultant R=sqrt(P^(2)+Q^(2)+2PQ cos theta).tan phi=(Q sin theta)/(P+Q cos theta).for (f_(1)+f_(2))+f_(3){:[R_(1)= vec(F)_(1)+ vec(F)_(2)quad theta=45^(@)],[F_(1)_(Delta theta=45^(@))],[R_(1)=sqrt(F_(1)^(2)+F_(2)^(2)+2cos theta xxF_(1)F_(2))],[=sqrt(4^(2)+6^(2)+2cos 45 xx4xx6)=9.27],[tan phi=(6sin 45^(@))/(4+6cos 45^(@))=(4.24)/(4+4.24)=0.514],[" Angle "b 100quad vec(R)" and " vec(F_(3))=90+phi=107.02],[phi_(2)=90+24_(2)=117.02.]:}{:[" Topic : "],[R= vec(R_(1))+ vec(F_(2))],[=sqrt((R_(1))^(2)+(F_(3))^(2)+2R_(1)F_(3)cos phi_(2))],[=sqrt((9.21^(2)+8^(2)+2xx9.27 xx8c ... See the full answer