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1.) ( x3y3 + 1 ) dx +
x4y2 dy = 0

Solve the differential equation using integrating factors

1.) ( x^{3}y^{3} + 1 ) dx +
x^{4}y^{2} dy = 0

Community Answer

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Solution: rarr According to the question, here we have ginen{:[(x^(3)y^(3)+1)dx+x^(4)y^(2)dy=0],[=>x^(4)y^(2)dy+(x^(3)y^(3)+1)dx=0]:}on divide by x^(4)y^(2)dx whole equation, we get.(dy)/(dx)+(1)/(x)*y=-(1)/(x^(4))*(1)/(y^(2))quad" (1) "Solve this equation by Bernaullis Equation. According to whichy^(-n)(dy)/(dn)+P*y^(-n+1)=Qwhere P and Q are funetion of xso. from (1)y^(2)(dy)/(dx)+(1)/(x)*y^(3)=-(1)/(x^(4))quad(2)Let y^(3)=v, on ... See the full answer

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