Please draw all needed F.B.D

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SolG+\Sigma M_{A}=0F_{B} \cos 40^{\circ}(1)+F_{B} \sin 40^{\circ}(1)-125(4)-600(9)=0\begin{array}{l}F_{B}=4188 \mathrm{~kb} \\F_{B}=4.19 \mathrm{kPp}\end{array}\begin{array}{l} \rightarrow \sum F_{x}=0 ; \\-A_{x}+4188 \cos 40^{\circ}=0 \\A_{x}=3208 \mathrm{lb} \\A_{x}=3.21 \mathrm{kip}\end{array}\begin{aligned}+\uparrow \sum F y & =0 ; \\& -A y+4188 \sin 40^{\circ}-600-125=0 \\\therefore A y & =1.97 \mathrm{kip}\end{aligned} ...