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FBO of crane boom\begin{array}{l}\sum F_{x}=0 \\A_{o c}+F_{B} \cos 40^{\circ}=0 \\\Sigma F_{y}=0 \\A_{y}+F_{B} \operatorname{Sin} 40^{\circ} \\=3000+625 \\=3625 \mathrm{~N} \rightarrow \text { (2) } \\\end{array}\begin{array}{c}\left(F_{B} \cos 40^{\circ}\right)(0.3)+\left(F_{B} \sin 40^{\circ}\right)(0.3) \\-(625)(1.2)-(3000)(2.7)=0 \\\therefore F_{B}=20.939 \mathrm{kN}(1)\end{array}from (1), (2), (3)\begin{array}{l} A_{x}=-16.04 \mathrm{kN}, \quad A_{y}=-9.83 \mathrm{kN} \\\therefore \quad A_{x} \mid=+16.04 \mathrm{kN} \quad(\leftarrow) \\\left|A_{y}\right|=+9.83 \mathrm{kN}(\downarrow)\end{array} ...