Question The cantilever shown below has a rectangular cross-section and bears a concentrated load F at the free end. If the yield stress is 350 MPa and the safety factor against yielding is nu, calculate the greatest possible value of F. - 2 m Select one: AF...8.2 kN B. F = 32.8 kN 100 mm - Cross-section C. Fra = 16.4 kN D. Fraz = 20.56 kN

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Transcribed Image Text: The cantilever shown below has a rectangular cross-section and bears a concentrated load F at the free end. If the yield stress is 350 MPa and the safety factor against yielding is nu, calculate the greatest possible value of F. - 2 m Select one: AF...8.2 kN B. F = 32.8 kN 100 mm - Cross-section C. Fra = 16.4 kN D. Fraz = 20.56 kN
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Transcribed Image Text: The cantilever shown below has a rectangular cross-section and bears a concentrated load F at the free end. If the yield stress is 350 MPa and the safety factor against yielding is nu, calculate the greatest possible value of F. - 2 m Select one: AF...8.2 kN B. F = 32.8 kN 100 mm - Cross-section C. Fra = 16.4 kN D. Fraz = 20.56 kN
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KWY5WS

Solution:-Now, By using Bending equation.{:[(sigma )/(y)=(m)/(I)=(E)/(R)],[sigma=(my)/(I)]:}Now,maximum bending mument[[sigma=," Bending stress "],[I=," moment of inertic "],[," about "x-x],[y=," Distance of ovter "],[," must fiber from "],[," neutrat axis. "]:}g. Stress ( max) and m=13 ending momen it will occures at bfixed end of cantitever{:[m_(m_(x))=F xx L=F xx2],[m_(max)=2F]:}:.sigma_(max)=(m_(max)xy)/(I)int_(max)=(2F xx y)/(I)Now, For Rectengular section given{:[I=(bh ... See the full answer