Question The decomposition of SO2Cl2 is first order in SO2Cl2 and has a rate constant of 1.42 * 10 - 4 s - 1 at a certain temperature. a. What is the half-life for this reaction? b. How long will it take for the concentration of SO2Cl2 to decrease to 25% of its initial concentration? c. If the initial concentration of SO2Cl2 is 1.00 M, how long will it take for the concentration to decrease to 0.78 M? d. If the initial concentration of SO2Cl2 is 0.150 M, what is the concentration of SO2Cl2 after 2.00 * 102 s? After 5.00 * 102 s?

0FC3Z6 The Asker · Chemistry

The decomposition of SO2Cl2 is first order in SO2Cl2 and has a rate constant of 1.42 * 10 - 4 s - 1 at a certain temperature. a. What is the half-life for this reaction? b. How long will it take for the concentration of SO2Cl2 to decrease to 25% of its initial concentration? c. If the initial concentration of SO2Cl2 is 1.00 M, how long will it take for the concentration to decrease to 0.78 M? d. If the initial concentration of SO2Cl2 is 0.150 M, what is the concentration of SO2Cl2 after 2.00 * 102 s? After 5.00 * 102 s?

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given, k (rate constant) =1.42 xx10^(-4)s^(-1)a) half-life (t_(1//2)) of finst order r xx n is,(b) Given{:[t_(1//2)=(0.673 )/(k)],[{:[=(0.673)/(1.42 xx10^(-4)st)=4739.44s],[=4.74 xx10^(3)s" Answer. "]:}]:}(A)=0.25(A)_(0)we know for 1 At order,{:[(A)=(A_(0))e^(-kt)quad(1)],[0.25(A_(0))=(A_(0))=e^(-kt)],[ln(0.25)=-kt],[t=-(-ln(0.25))/()=k],[t=(ln(0.25))/(1.42 xx10^(-4)s^(-1))=9762.64s],[t=9.76 xx10^(3)s]:}( ... See the full answer