Question The manager of a night club in Boston stated that 90% of the customers are between the ages of 22 and 26 years. If the age of customers is normally distributed with a mean of 24 years, calculate its standard deviation. (You may find it useful to reference the z table. Round "z" value to 3 decimal places and final answer to 2 decimal places.) Standard deviation 1.00

BEZZYH The Asker · Probability and Statistics

Transcribed Image Text: The manager of a night club in Boston stated that 90% of the customers are between the ages of 22 and 26 years. If the age of customers is normally distributed with a mean of 24 years, calculate its standard deviation. (You may find it useful to reference the z table. Round "z" value to 3 decimal places and final answer to 2 decimal places.) Standard deviation 1.00
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Transcribed Image Text: The manager of a night club in Boston stated that 90% of the customers are between the ages of 22 and 26 years. If the age of customers is normally distributed with a mean of 24 years, calculate its standard deviation. (You may find it useful to reference the z table. Round "z" value to 3 decimal places and final answer to 2 decimal places.) Standard deviation 1.00
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P(-2/s.d.&lt;Z &lt;2/s.d.)=0.9 Using normal distribution table find Z=1.645 2/s.d.=1.645 we get S. D. =2/1.645=1.216=1.22&#160; &#160;(in 2 decimal)&#160; Standard deviation(s.d.) = 1.22 Solution file is attached go through it Sol&quot; Manger of night club in Boston sitated that 90% of custirmess are between ages of 22 and 26 years i.e. P(22 < x < 26)=0.90If Customers is nomally Distribyted with mean =24 years calculate its standared Deritition using 2-s are =(x-mu)/(T){:[P((22-mu)/(sigma) < (x-mu)/(sigma ... See the full answer