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for the given message signal m(t) here, we ortain the bollowirg from the provided circuit.(a) m(t)(b) Output of PM movilator: A_(c)cos(omega_(c)t+k_(p)m(t)). where, A_(c)=1V,omega_(c)*2pit_(c)xxA_(c)=100kHIz. Further, here we observe instantanerw frequency f_(i)=f_(c)+(k_(k))/(2pi)m^(˙)(t) unere m^(˙)(t)=(d)/(dt)m(t).Hena we rotain nere the bollowirg.:. Hera frequency deviation Delta f*(k_(p))/(2pi)xx1000*9kHz. Hence wavesom at (5) wis be the bolliviris.(c) Output here woreas be, -A_(e)[omega_(c)+K_(p)m(t)]si ... See the full answer