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Answer: \begin{aligned}\text { UDP payload in each frame } & =\text { frame size }-(\text { UDP header }+ \text { IP header }) \\& =1500-(20+8) \\& =1472 \text { bytes. }\end{aligned}Number of packets can be sent to transfer the entire file =\frac{\text { File size }}{\text { UDP payload }}\begin{array}{l}=\frac{24000000}{1472} \\=16304.34 \\\approx 16305 \text { packets. }\end{array}[round off the point, for easy calculation]Therefore, the number of packets can be sent to transfer the entire file is 16305 packets\begin{aligned}\text { Total bytes needed } & =(\text { File size })+(\text { Headers }) * \text { Number of packets to be sent } \\& =24000000+28 * 16305 \\& =24000000+456540 \\& =24456540 \text { bytes. }\end{aligned} Please give thumbsup, if you like it. Thanks. ...