The probability that a patient recovers from a stomach disease is 0.6. Suppose 20 people are known to have contracted this disease. (Round your answers to three decimal places.)

A) What is the probability that exactly 13 recover?

B) What is the probability that at
least 11 recover?

C) What is the probability that at least 13 but not more
than 19 recover?

D) What is the probability that at most 15 recover?

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Solution:- Let x be the number of patient recovers from a stomach disease.{:[X∼Binomial(n=20","p=0.6)],[P(x=x)=([20],[x])(0.6)^(x)(0.4)^(20-x)quad x=0.1","2dots20]:}(A){:[P(X=13)],[=([20],[13])(0.6)^(13)(0.4)^(7)],[=0.166" Ans "]:}(B){:[P(x⩾11)],[=sum_(x=11) ... See the full answer