Question Solved1 Answer The reaction between sulfur dioxide and oxygen according to the equation below is reversible: 2SO2(g) + O2(g) = 2503(g) What will happen when a sample of sulfur dioxide and oxygen are mixed in a reactor? The concentration of the O2 will always be half that of the SO2. The concentration of the SO3 will increase at double the rate the O2 concentration is decreasing The concentration of the SO3 is increasing at the same rate the SO2 concentration is increasing The concentration of the SO3 will increase at the same rate the O2 concentration is decreasing

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Transcribed Image Text: The reaction between sulfur dioxide and oxygen according to the equation below is reversible: 2SO2(g) + O2(g) = 2503(g) What will happen when a sample of sulfur dioxide and oxygen are mixed in a reactor? The concentration of the O2 will always be half that of the SO2. The concentration of the SO3 will increase at double the rate the O2 concentration is decreasing The concentration of the SO3 is increasing at the same rate the SO2 concentration is increasing The concentration of the SO3 will increase at the same rate the O2 concentration is decreasing
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Transcribed Image Text: The reaction between sulfur dioxide and oxygen according to the equation below is reversible: 2SO2(g) + O2(g) = 2503(g) What will happen when a sample of sulfur dioxide and oxygen are mixed in a reactor? The concentration of the O2 will always be half that of the SO2. The concentration of the SO3 will increase at double the rate the O2 concentration is decreasing The concentration of the SO3 is increasing at the same rate the SO2 concentration is increasing The concentration of the SO3 will increase at the same rate the O2 concentration is decreasing
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Here in this question,  The reaction given to us is ,  2SO2 +O2 <==> 2SO3. HERE THE ANSWER WILL BE OPTION B. REASON , I'm option a the concentration of O2 will not always be half of SO2. As , it depend on the initial conditions, suppose at the starting of the reaction in the reactor ,the propotiom was not half but then slowly equilibrium reached and the ratio is acquired . So we can't say always it was and will be half. Now , the rate equat ... See the full answer