Question Solved1 Answer The reaction between sulfur dioxide and oxygen according to the equation below is reversible: 2SO2(g) + O2(g) = 2503(g) What will happen when a sample of sulfur dioxide and oxygen are mixed in a reactor? The concentration of the O2 will always be half that of the SO2. The concentration of the SO3 will increase at double the rate the O2 concentration is decreasing The concentration of the SO3 is increasing at the same rate the SO2 concentration is increasing The concentration of the SO3 will increase at the same rate the O2 concentration is decreasing

The amount of light absorbed in spectroscopy is defined by Choose... solute rate increase supersaturated molality transmittance equilibrium Le Chatelier's Principle absorbance

At its Ames Research Center, NASA uses its large “20 G” centrifuge to test the effects of very large accelerations (“hypergravity”) on test pilots and astronauts. In this device, an arm 8.84 m long rotates about one end in a horizontal plane, and an astronaut is strapped in at the other end. Suppose that he is aligned along the centrifuge’s arm with his head at the outermost end. The maximum sustained acceleration to which humans are subjected in this device is typically 12.5g. (a) How fast must the astronaut’s head be moving to experience this maximum acceleration? (b) What is the difference between the acceleration of his head and feet if the astronaut is 2.00 m tall? (c) How fast in rpm 1rev>min2 is the arm turning to produce the maximum sustained acceleration?

Consider the Lotka-Volterra predator-prey model defined by\[$\begin{array}{l}\frac{d x}{d t}=-0.1 x+0.02 x y \\\frac{d y}{d t}=0.2 y-0.025 x y\end{array}$\]where the populations x(t) (predators) and y(t) (prey) are measured in thousands. Suppose $x(0)=6$ and $y(0)=6$ . Use a numerical solver to graph x(t) and y(t) . Use the graphs to approximate the time t>0 when the two populations are first equal. Use the graphs to approximate the period of each population.

Consider this equation, where $a$ , $b$ and $k$ are constants, $$\frac{dy}{dt} = k(a-y)(b-y)$$ Assuming an initial condition $y=0$ at $t=0$ Solve this equation for $y(t)$ for the case $a=b$ . Solve this equation for the case $0 \lt a \lt b$ By considering the limit $b \rightarrow a$ in 2) show that the two results are consistent with each other. So I am confident with my result for (i), through separating the variables, integrating then finding the constant of integration by using the initial conditions, resulting in: $$y(t) = -\frac{1}{kt}$$ However I am confused as to how to solve for the case of limits ? Any help would be appreciated.

8.84 m At its Ames Research Center, NASA uses its large "20-G" centrifuge to test the effects of very large accelerations ("hypergravity") on test pilots and astronauts. In this device, an arm 8.84 m long rotates about one end in a horizontal plane, and an astronaut is strapped in at the other end. Suppose that he is aligned along the centrifuge's arm with his head at the outermost end. The maximum sustained acceleration to which humans are subjected in this device is typically 12.5g. Use g = 10 m/s2 A. How fast (in m/s) must the astronaut's head be moving to experience this maximum acceleration? B. How fast in rpm (rev/min) is the arm of the device turning to produce the maximum sustained acceleration? Enter a positive number. C. How fast (in m/s) are the astronaut's feet moving if he is 2.00 m tall, and the arm is rotating with the speed found in (B)? D. What is the difference between the centripetal acceleration of his head and feet? Express your answer in m/s2 and enter a positive number.

47-58 - Composition of Functions Find the functions $f \circ g$ , $g \circ f, f \circ f$ , and $g \circ g$ and their domains.