# Question Solved1 AnswerThe reduced row-echelon form of the augmented matrix for a system of linear equations with variables x1, ... , x5 is given below. Determine the solutions for the system and enter them below. 1 0 0 5 0 4 0 1 -3 -4 0-4 0 0 0 0 1-2 If the system has infinitely many solutions, select "The system has at least one solution". Your answer may use expressions involving the parameters r, s, and t. The system has at least one solution X1 = 0 X2 = 0 X3 = 0 X4 = 0 15= 0

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Transcribed Image Text: The reduced row-echelon form of the augmented matrix for a system of linear equations with variables x1, ... , x5 is given below. Determine the solutions for the system and enter them below. 1 0 0 5 0 4 0 1 -3 -4 0-4 0 0 0 0 1-2 If the system has infinitely many solutions, select "The system has at least one solution". Your answer may use expressions involving the parameters r, s, and t. The system has at least one solution X1 = 0 X2 = 0 X3 = 0 X4 = 0 15= 0
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Transcribed Image Text: The reduced row-echelon form of the augmented matrix for a system of linear equations with variables x1, ... , x5 is given below. Determine the solutions for the system and enter them below. 1 0 0 5 0 4 0 1 -3 -4 0-4 0 0 0 0 1-2 If the system has infinitely many solutions, select "The system has at least one solution". Your answer may use expressions involving the parameters r, s, and t. The system has at least one solution X1 = 0 X2 = 0 X3 = 0 X4 = 0 15= 0
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General GuidanceThe answer provided below has been developed in a clear step by step manner.Step: 1M The reduced now-echelon form of the augmented matrix for a system of linear equations with variables x_(1),x_(2),cdots,x_(5) is[A\\b]=[[1,0,0,5,0,4],[0,1,-3,-4,0,-4],[0,0,0,0,1,-2]]ltore,{:[" number of "],[rante(A)=" non-zero now in "=3],[" first "5" columns "],[rank([A∣b])=" no. of non-zero "=3],[" nows in "],[" echelon form "]:}Hence, rank (A)= rank [[A(b])=3 < nariables => The system has infinitely many solutions.from g ... See the full answer