# Question Solved1 Answer​​​​​​​ The rms permanent magnet flux linkage phasor of a 3-phase, 2-pole-pair, sine wave permanent magnet servo motor is given by $\Psi_{p m}=0.1(\mathrm{rms} W b) \angle(-\pi / 3)(\mathrm{rad})$ To achieve $$13.4 \mathrm{Nm}$$ torque under maximum torque per Ampere operation, the rms current is XQ520E The Asker · Electrical Engineering ​​​​​​​

Transcribed Image Text: The rms permanent magnet flux linkage phasor of a 3-phase, 2-pole-pair, sine wave permanent magnet servo motor is given by $\Psi_{p m}=0.1(\mathrm{rms} W b) \angle(-\pi / 3)(\mathrm{rad})$ To achieve $$13.4 \mathrm{Nm}$$ torque under maximum torque per Ampere operation, the rms current is
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Transcribed Image Text: The rms permanent magnet flux linkage phasor of a 3-phase, 2-pole-pair, sine wave permanent magnet servo motor is given by $\Psi_{p m}=0.1(\mathrm{rms} W b) \angle(-\pi / 3)(\mathrm{rad})$ To achieve $$13.4 \mathrm{Nm}$$ torque under maximum torque per Ampere operation, the rms current is    