Step1/2.gkwtCW{margin:0;font-family:"Aspira Webfont","Helvetica","Arial",sans-serif;display:-webkit-box;display:-webkit-flex;display:-ms-flexbox;display:flex;-webkit-flex-direction:column;-ms-flex-direction:column;flex-direction:column;gap:16px;}/*!sc*/data-styled.g379[id="sc-z3f5s1-0"]{content:"gkwtCW,"}/*!sc*/.iIwMoS{white-space:pre-wrap;}/*!sc*/data-styled.g381[id="sc-1aslxm9-0"]{content:"iIwMoS,"}/*!sc*/.fzJtOB{text-align:start;}/*!sc*/data-styled.g383[id="sc-1aslxm9-2"]{content:"fzJtOB,"}/*!sc*/.hOZehF{margin:0;font-family:"Aspira Webfont","Helvetica","Arial",sans-serif;}/*!sc*/data-styled.g410[id="sc-9wsboo-0"]{content:"hOZehF,"}/*!sc*/.lhIoTe{margin:0;font-size:1rem;}/*!sc*/data-styled.g412[id="sc-1swtczx-0"]{content:"lhIoTe,"}/*!sc*/.iHelzO{margin:0;font-family:"Aspira Webfont","Helvetica","Arial",sans-serif;line-height:normal;}/*!sc*/data-styled.g445[id="sc-1sugbjn-0"]{content:"iHelzO,"}/*!sc*/.kkKaFK{margin-top:14px;}/*!sc*/data-styled.g449[id="sc-1sugbjn-4"]{content:"kkKaFK,"}/*!sc*/.iQllJf{margin-top:14px;}/*!sc*/data-styled.g450[id="sc-1sugbjn-5"]{content:"iQllJf,"}/*!sc*/To solve this problem, we need to use the formula for torque in a permanent magnet servo motor, which is given by:T = Kt * I * ψmWhere T is the torque, Kt is the torque constant, I is the current, and ψm is the magnet flux linkage.Given that the rms permanent magnet flux linkage phasor is:ψm = 0.1(rms Wb) * (-π/3) (rad)And we are trying to achieve a torque of 13.4 Nm under maximum torque per ampere operation.Explanation:We can now substitute the given values into the torque formula and solve for I:Step2/2.gkwtCW{ ... See the full answer