【General guidance】The answer provided below has been developed in a clear step by step manner.Step1/3Given \( \begin{align*} \mathrm{{v}} &= \mathrm{{4.5}{t}+{2.4}{t}^{{{2}}}+{1.1}{t}^{{{3}}}} \end{align*} \)we have to calculate acceleration at t = 3.0 s Explanation:here of use differentiation to find acceleration at 3 s .Step2/3since acceleration: change in velocity with respect to time i.e a = dv/dt\( \begin{align*} \mathrm{{a}} &= \mathrm{\frac{{{d}{\left({4.5}{t}+{2.4}{t}^{{{2}}}+{1.1}{t}^{{{3}}}\right)}}}{{{\left.{d}{t}\right.}}}} \\[3pt]\mathrm{{a}} &= \ ... See the full answer