Three telephone booths, P, Q and R, are on the same level ground such that P is due south of Q and R is on a bearing 0f 75 degrees from Q. the bearing of R from P is 39 degrees. A vertical tower TQ is situated at Q. Given that TQ = 25 m and QR = 87 m, calculate:

- The distance PR to the nearest meter.
- The angle of elevation of T from P.

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Step 1We know that{:[/_RQP+/_QPR+alpha=180^(@)],[75^(@)+39^(@)+alpha=180^(@)],[alpha=66^(@)]:}From sine formula{:[(PR)/(sin Q)=(QR)/(sin P)=(PQ)/(sin alpha)],[:.(PR)/(sin 75^(@))=(87)/(sin 39^(@))] ... See the full answer