Question Trevel Expenses Employees are categorised into three travel expense brackets. - Expense categorisatlon is calculated by dividing total cost expensed by hours worked. - Cost bracket for Managers and Senlor Managers is \( 1.5 \) times basic rate. - Basic rate for high cost bracket is above 19 - Basic rate for mid cost bracket is between \( \mathbf{1 1} \) and \( \boldsymbol{1 9} \) - Basic rato for low cost brackot is loss than 11

Old MathJax webview Alice received the following ciphertext from Bob, "12 15 15 26". Bob had encrypted it using the RSA cypher with Alice's public key (pq, e) = (55 a positive inverse for 3 modulo (p-1)(9 - 1). It was found to be 27 in Examples 8.4.8(b) and 8.4.10. What is Bob's message after Alice decry To decrypt Bob's message, Alice uses the decryption formula M=d mod where M is the code for a letter of the message, C is the encrypted version of the letter, (pq, e) = (55, 3) is the public key, and (pq, d) = (55, 27 (a) To begin, Alice computes the values of a, b, c, d and e that are indicated below. 121= a (mod 55) 122 = b (mod 55) 124 = c(mod 55) 128 = d (mod 55) 1216 = e (mod 55) She finds that a = b = d = and e = Because 27 = 16 + 8 + 2 + 1, 1227 - 1216 + 8 +2+1 = 1216. 128. 122. 121, she uses the values of a, b, d, and e to compute 1227 mod 55 = (a.b d. e) mod 55 = Thus, the first letter in Bob's message is (b) Alice finds the second letter of Bob's message by computing mod 55 = (C) What is Bob's message after Alice finishes decrypting it? ASK YOUR TEACHER Alice received the following ciphertext from Bob, "12 15 15 26". Bob had encrypted it using the RSA cypher with Alice's public key (pq, e) = (55, 3), where p = 5 and q = 11. Note that (p-1)(0 - 1) = 40. The value for d in Alice's private key, (pq, d) is a positive inverse for 3 modulo (p - 1)(9 - 1). It was found to be 27 in Examples 8.4.8(b) and 8.4.10. What is Bob's message after Alice decrypts it? (Assume Bob encoded one letter at a time using the encoding A = 01, B = 02, C = 03,...,Z = 26.) To decrypt Bob's message, Alice uses the decryption formula M = C mod where M is the code for a letter of the message, C is the encrypted version of the letter, (pq, e) = (55, 3) is the public key, and (pq, d) = (55, 27) is the private key. (a) To begin, Alice computes the values of a, b, c, d and e that are indicated below. 121 = a (mod 55) 122 = b (mod 55) 124 = c(mod 55) 128 = d (mod 55) 1216 ze (mod 55) She finds that a = b = CE d = and e = Because 27 = 16 + 8 + 2 + 1, 1227 = 1216 + 8 + 2 + 1 = 1216. 128. 122. 121, she uses the values of a, b, d, and e to compute 1227 mod 55 = (a.b.de) mod 55 = Thus, the first letter in Bob's message is mod 55 (b) Alice finds the second letter of Bob's message by computing (c) What is Bob's message after Alice finishes decrypting it?

Shelly and Kelly Macdonald met up with Sarah and Tara MacNeill to go fishing in Cape Breton. They found two pools in a stream containing speckled trout (assume equal variance), with the Macdonalds at one pool and the MacNeills at the other, and at the end of the day each team had caught (and released unharmed) 5 fish. For each fish they recorded the length and weight, and the data on length (in cm) is summarized below (Give the answers to 2 places past decimal) Team Macdonald MacNeill Mean 18.1 20.35 Std.Dev 1.4 1.9 a.) To test whether or not the fish have the same mean size in the two pools, the null hypothesis will be: HO: 1-X 2 = -2.25 HO: p1-y2 = -2.25 HO: X 1-8 2 = 0 HO: 1-2 = 0 # Tries 0/1 b.) The alternative hypothesis for this test will be: Ha: * 1- 2 = -2.25 Ha: p1-12 + -2.25 Ha: 81-X 2 = 0 Ha: p1-42 = 0 1236 Tries 0/1 c.) What is the pooled estimate of the variance? 1202 Tries 0/5 d.) Compute the value of the test statistic. 1 Tries 0/5

A 50-g weight is hung at the 20-cm mark of a meterstick and a 100-g weight is hung at the 70-cm mark. At what point must the meterstick be supported for it to be in rotational equilibrium? The weight of the meterstick is negligible. O at the 56.67-cm mark. at the 46.67 cm mark. O at the 53.33-cm mark. O at the 43.33 cm mark.

Part A The post is made of Douglas fir and has a diameter of 100 mm (Figure 1) It is subjected to the load of 20 kN and the soil provides a frictional resistance distributed around the post that is triangular along its sides that is, it varies from w=0 kN/mat y=0 m to w= 15 kN/m at y = 2 m. Neglect the weight of the post Determine the force at its bottom needed for equilibrium Express your answer to three significant figures and include appropriate units. HÅ ? Value Units Submit Request Answer Figure 1 of 1 Part B 20KN What is the displacement of the top of the post with respect to a bottom B? Express your answer to three significant figures and include appropriato unito, ? 2 m 0 = Value Units 12 kN/m Submit Request Answer

​​​​​​​ The bar has a cross-sectional area of \( 1900 \mathrm{~mm}^{2} \) and \( E=250 \mathrm{GPa} \). (Figure 1) Determine the displacement of its end \( A \) when it is subjected to the distributed loading. Express your answer to three significant figures and include the appropriate units. Enter negative value in the case of contraction and positive value in the case of elongation. Figure 1 of 1 X Incorrect; Try Again; 4 attempts remaining

      please solve all tasks A car rental company owns five types of cars: Small, Economy, Standard, Family, Exclusive. The prices for per day rent for each type of the cars aregiven in British pounds by the \( 1 \times 5 \) matrix \[ \mathbf{p}=\left(\begin{array}{lllll} 15 & 19 & 21 & 28 & 37 \end{array}\right) \] The care demand for five days of a week ahead is given by the matrix \[ \mathbf{A}=\left(\begin{array}{ccccc} 2 & 4 & 3 & 1 & 3 \\ 4 & 3 & 3 & 5 & 3 \\ 10 & 11 & 8 & 6 & 9 \\ 4 & 3 & 2 & 3 & 4 \\ 2 & 1 & 3 & 2 & 1 \end{array}\right) \] Calculate the total income in British pounds of the company for this week. a. 10500 b. 3420 C. 2242 d. 4520 Consider the clockwise rotation \( T \) of \( \mathbb{R}^{2} \) by the angle of \( 30^{\circ} \). Mark only correct statements. a. The matrix of \( T \) is \( \left(\begin{array}{cc}-\frac{\sqrt{3}}{2} & \frac{1}{2} \\ \frac{1}{2} & -\frac{\sqrt{3}}{2}\end{array}\right) \) b. The matrix of \( T \) is symmetric. c. The matrix of \( T \) is \( \left(\begin{array}{rr}\frac{\sqrt{3}}{2} & -\frac{1}{2} \\ \frac{1}{2} & \frac{\sqrt{3}}{2}\end{array}\right) \) d. The matrix of \( T \) is \( \left(\begin{array}{cc}\frac{\sqrt{3}}{2} & \frac{1}{2} \\ -\frac{1}{2} & \frac{\sqrt{3}}{2}\end{array}\right) \) e. The matrix of \( T \) is \( \left(\begin{array}{cc}\frac{\sqrt{3}}{2} & \frac{1}{2} \\ -\frac{1}{2} & \frac{\sqrt{3}}{2}\end{array}\right) \) A company manufactures three types of perfume-refreshing \( (R) \), standard \( (S) \), and exclusive \( (E) \), in four factories in different countries \( A \), B, C, D. The distributions of costs in producing a single piece of perfume are given in the left table below. The number of pieces of perfume produced in one month at the four locations are given in the right table. a. Location A materials: \( \$ 4500 \) b. Location B: labor \( \$ 8000 \) c. Location A: labor \( \$ 14000 \) d. Location D: materials \( \$ 25000 \) e. Location C: overheads \( \$ 16000 \)