Two 2.00-μC\mu CμC point charges are located on the x axis. One is at x = 1.00 m, and the other is at x = −1.00 m. (a) Determine the electric field on the y axis at y = 0.500 m. (b) Calculate the electric force on a −3.00-μC\mu CμC charge placed on the y axis at y = 0.500 m

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Step 1Given: q_(1)=q_(2)=2muC=2xx10^(-6)C{:[x=d=1m],[y=0.5m],[ vec(E_(1))=(Kq_(1))/(l^(2))=((9xx10^(9))(2xx10^(-6)))/((1.118)^(2))],[[ vec(E_(1))=14.4 xx10^(3)(N)//C]]:}Here, l=sqrt(d^(2)+y^(2))l=sqrt((1)^(2)+(0.5)^(2))=1.118mSincilarly,{:[ vec(E)_(2)=(Kq_(2))/(l^(2))=((9xx10^(9))(2xx10^(-6)))/((1.11)^(2))=14.4 xx10^(3)N//C],[[ vec(E)_(2)=14.4 xx10^(3)(N)//C]]:}Geometry;theta=tan^(-1)((d)/(y))=tan^(-1)((1)/(0.5))=63.435^(@)So, Angle between vec(E_(1))& vec(E_(2)) ... See the full answer