Two 5.00 μF capacitors are
connected to each other in series and are then connected to
a 6.00 V battery.
(please provide simple illustrations and point out formulas
applied)
Calculate the charge on each capacitor (give two separate answers, one for each capacitor).
The capacitors are now disconnected from the battery, and wax (κ = 4.00) is inserted into one of the two capacitors. Calculate the potential difference across the series combination after the wax is inserted.
How much work is done by electrostatic forces on the wax as it is inserted into the capacitor?
The capacitors are now disconnected from each other and then reconnected in parallel (positive plate to positive plate; negative plate to negative plate). This is done carefully, so as to not accidentally discharge the capacitors.
Determine the resulting charge on each capacitor after equilibrium is reestablished. (Hint: what is the voltage across each capacitor?)
How much energy is converted to thermal energy in the resistance of the connecting wires while the charges rearrange themselves to reestablish equilibrium?
Ans- The  capacitance of net capacitor  1/C = 1/5 +1/5 ,  C = 5/2 muF  Ansa-  Charge on each capacitor Q =CV = 5×6/2 =15muC Ansb-  Since the wax (k =4) is inserted in one of the capacitor then the potential accross the series combination after the wax is inserted,,  V = 3 +3/4 = 15/4 volt Ansc -  Work done by electrostatistic force to insert the the wa ... See the full answer