Question Two circular disks spaced 0.50 mm apart form a parallel-plate capacitor. Transferring 5.00×109 electrons from one disk to the other causes the electric field strength to be 1.00×105 N/C. For help with math skills, you may want to review: Rearrangement of Equations Involving Multiplication and Division Mathematical Expressions Involving Squares Part A What Two circular disks spaced 0.50 mm apart form a parallel-plate capacitor. Transferring 5.00×109 electrons from one disk to the other causes the electric field strength to be 1.00×105 N/C. For help with math skills, you may want to review: Rearrangement of Equations Involving Multiplication and Division Mathematical Expressions Involving Squares Part A What are the diameters of the disks? Express your answer with the appropriate units. ▸ View Available Hint(s) μÁ ? D= 0.00188 m

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Transcribed Image Text: Two circular disks spaced 0.50 mm apart form a parallel-plate capacitor. Transferring 5.00×109 electrons from one disk to the other causes the electric field strength to be 1.00×105 N/C. For help with math skills, you may want to review: Rearrangement of Equations Involving Multiplication and Division Mathematical Expressions Involving Squares Part A What are the diameters of the disks? Express your answer with the appropriate units. ▸ View Available Hint(s) μÁ ? D= 0.00188 m
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Transcribed Image Text: Two circular disks spaced 0.50 mm apart form a parallel-plate capacitor. Transferring 5.00×109 electrons from one disk to the other causes the electric field strength to be 1.00×105 N/C. For help with math skills, you may want to review: Rearrangement of Equations Involving Multiplication and Division Mathematical Expressions Involving Squares Part A What are the diameters of the disks? Express your answer with the appropriate units. ▸ View Available Hint(s) μÁ ? D= 0.00188 m
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The Electric field strength between plates of a capacitors is given by,  E = Q/AE0  Where, Q = n* e = 5*109 *1.6*10-19 = 8*10-10 C A = area of plate = π*r2 Now, substituting the values we have,  ... See the full answer