Two reservoirs A and B have elevations of 250m and 100m respectively. It is connected by a pipe having a diameter of 250mm and a length of 100m. A turbine is installed at point in between reservoirs A and B. If C = 120, compute the following if the discharge flowing in the pipeline is 150 liters/sec. Compute the power generated by the turbine.

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Step 1Given data in question Elevations Discharge Diameter LengthConstant valueTo find out Power of pumpStep 2Sol: \quad g=150 \mathrm{l} / \mathrm{s}=0.15 \mathrm{~m}^{3} / \mathrm{s}Apply Bumanti b / w A \& \&.\begin{array}{l}\frac{P_{A}}{\rho g}+\frac{V_{A}^{2}}{2 g}+Z_{A}=\frac{P_{B}}{\rho g}+\frac{V_{B}^{2}}{2 g}+Z_{B}+h_{l}+h_{f} \\0+0+250=0+0+100+h_{l}+h_{f} \\250-100=h_{l}+h_{f} \\\text { whure } \quad h_{l}=\frac{10.64 \times L \times g^{1.85}}{12.1 .85} \times 0.25^{4.87} \\L=100 \mathrm{~m} \\C=120 \\D=250 \mathrm{~mm}=0.25 \mathrm{~m} \\h_{l}=3.8750 \\\Rightarrow 150=3.8750+h_{f} \\h_{f}=146.1250 \mathrm{~m} \\P=g g Q \times h_{l} \\P=1000 \times 9.81 \times 0.15 \times 146.125\end{array}Step 3\begin{array}{l}P=214994 \text { Watt } \\ P=214.994 \text { <watt }\end{array} ...