Question Solved1 Answer Use the Composite Midpoint rule with n +2 subintervals to approximate the integrals in Exercise 2. 0.5 b. x In(x + 1) dx, n = 6 -0.5

Absorption of Ammonia in a Packed Tower. A gas stream contains 4.0 mol % NH3 and its ammonia content is reduced to 0.5 mol % in a packed absorption tower at 293 K and 1.013 × 10 5 Pa. The inlet pure-water flow is 68.0 kg mol/h and the total inlet gas flow is 57.8 kg mol/h. The tower diameter is 0.747 m. The film mass-transfer coefficients are  a = 0.0739 kg mol/s · m3 · mol frac and  mol/s · m3 · mol frac. Using the design methods for dilute gas mixtures, do as follows: a. Calculate the tower height using.   b. Calculate the tower height using

i-3% 2004 200350 Calculate the unknown values. Use the compound interest calculations. The interest rates are annual, and each time unit is one year. (Do not round at intermediate steps!) Round your FINAL answer to the nearest integer. (For example, if you get 2.1, then round it to 2. If you get 2.8, then round it to 3.If you get 2.5, then round it to 3.)

The effect of temperature on the rate of a reaction was studied and the following data obtained: k (5-1) T(°C) 1.63X10-4 6 1.92 x 10-4 8 2.86X10-4 13 3.89 x 10-4 17 5.65x10-4 22 1.00X10-3 30 1.15x10-3 32 1.41 x 10-3 35 It is known that the variation of the rate constant k with the absolute temperature T is described by the Arrhenius equation: k = A exp [(-E, (RT)] where Ez is the activation energy, R is the universal gas constant and A is the pre-exponential factor (units of the rate constant). Taking the natural logarithm of both sides affords: E In k = In A - RT For a plot of y = In k versus x = 1/T, calculate the slope of the best straight line using linear regression. 1 pts Submit Answer Tries 0/99 Calculate the activation energy Ea. 1 pts

"Simon Says" is a memory game where "Simon" outputs a sequence of 10 characters \( (R, G, B, Y \) ) and the user must repeat the sequence, Create a for loop that compares the two strings starting from index 0 . For each match, add one point to userScore Upon a mismatch, exit the loop using a break statement. Assume simonPattern and userPattern are always the "Simon Says" is a memory game where "Simon" outputs a sequence of 10 characters (R,G,B,Y ) and the user must repeat the sequence, Create a for loop that compares the two strings starting from index 0 . For each match, add one point to userScore Upon a mismatch, exit the loop using a break statement. Assume simonPattern and userPattern are always the same length. Ex The following patterns yield a userScore of 4 : simonPattern: RRGBRYYBGY userPattern: RRGBBRYBGY 3 public class SimonSays \{ 4 public static void main (String □ args) \{ 5 Scanner scnr = new Scanner(System, in) 6 String simonPattern; 7 String userPattern; 8 int userscore; int i; user 5 core =0; simonPattern = scnr. next ); userPattern = scnr, next O; System. out.println("userScore: "+ userScore);

"Simon Says" is a memory game where "Simon" outputs a sequence of 10 characters (R, G, B, Y) and the user must repeat the sequence. Create a for loop that compares the two strings starting from index 0. For each match, add one point to userScore. Upon a mismatch, exit the loop using a break statement. Assume simonPattern and userPattern are always the same length.Ex: The following patterns yield a userScore of 4:simonPattern: RRGBRYYBGY userPattern: RRGBBRYBGY import java.util.Scanner;public class SimonSays {public static void main (String [] args) {Scanner scnr = new Scanner(System.in);String simonPattern;String userPattern;int userScore;int i;userScore = 0;simonPattern = scnr.next();userPattern = scnr.next();/* Your solution goes here */System.out.println("userScore: " + userScore);return;}} 

"Simon Says"simonPattern: RRGBRYYBGYuserPatteen: RRGBBRYBGY "Simon Says" is a memory game where "Simon" outputs a sequence of 10 characters (R, G, B, Y) and the user must repeat the sequence Create a for loop that compares the two strings starting from index 0. For each match, add one point to userScore. Upon a mismatch, exit the loop using a break statement. Assume simonPattern and userPattern are always the same length. Ex: The following patterns yield a userScore of 4: simonPattern: RRGBRYYBGY userPattern: RRGBBRYBGY 1 import java.util.Scanner; 2 3 public class SimonSays { 4 public static void main(String[] args) { 5 7 9 10 11 12 13 14 15 Scanner scnr- new Scanner(System.in); String simonPattern; String userPattern; int userScore; int i; userScore - 0; simonPattern scnr.next(); userPattern = scnr.next(): DID!! p d