QUESTION

Use the Heisenberg uncertainty principle to calculate Δx for an electron with Δv = 0.895 m/s.

By what factor is the uncertainty of the (above) electron's position larger than the diameter of the hydrogen atom?
(Assume the diameter of the hydrogen atom is 1.00×10-8 cm.)

Use the Heisenberg uncertainty principle to calculate Δx for a ball (mass = 150 g, diameter = 6.85 cm) with Δv = 0.895 m/s.

The uncertainty of the (above) ball's position is equal to what factor times the diameter of the ball?

Public Answer

BNLS1C The First Answerer