Question Solved1 Answer Water at 20°C flows steadily through the piping junction shown, entering section 1 at 20 gal/min. The average velocity at section 2 is 2.5 m/s. A portion of the flow is diverted through the showerhead, which contains 100 holes of 1-mm diameter. (A) Assuming uniform shower flow, estimate the exit velocity from the showerhead jets. (B) What pressure is required at (1) to produce this flow? Water at 20°C flows steadily through the piping junction shown, entering section 1 at 20 gal/min. The average velocity at section 2 is 2.5 m/s. A portion of the flow is diverted through the showerhead, which contains 100 holes of 1-mm diameter. (A) Assuming uniform shower flow, estimate the exit velocity from the showerhead jets. (B) What pressure is required at (1) to produce this flow? d-4 cm d1.5 cm d 2 cm

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Water at 20°C flows steadily through the piping junction shown, entering section 1 at 20 gal/min. The average velocity at section 2 is 2.5 m/s. A portion of the flow is diverted through the showerhead, which contains 100 holes of 1-mm diameter. (A) Assuming uniform shower flow, estimate the exit velocity from the showerhead jets. (B) What pressure is required at (1) to produce this flow?

Transcribed Image Text: Water at 20°C flows steadily through the piping junction shown, entering section 1 at 20 gal/min. The average velocity at section 2 is 2.5 m/s. A portion of the flow is diverted through the showerhead, which contains 100 holes of 1-mm diameter. (A) Assuming uniform shower flow, estimate the exit velocity from the showerhead jets. (B) What pressure is required at (1) to produce this flow? d-4 cm d1.5 cm d 2 cm
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Transcribed Image Text: Water at 20°C flows steadily through the piping junction shown, entering section 1 at 20 gal/min. The average velocity at section 2 is 2.5 m/s. A portion of the flow is diverted through the showerhead, which contains 100 holes of 1-mm diameter. (A) Assuming uniform shower flow, estimate the exit velocity from the showerhead jets. (B) What pressure is required at (1) to produce this flow? d-4 cm d1.5 cm d 2 cm
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calcuate the flow rate of water at secton 2{:[Q_(2)=A_(2)v_(2)],[{:=C(pi)/(4)xx0.02^(2)]xx2.5]:}worte the conversion to convert flow rabe from gal//min to m^(3)//s1gal//min=6-31 xx10^(-5)m^(3)//sconvert the flow rale of water at sectur 1 rrom gal/min to m^(3)//s{:[20" gal "//min=20 xx6.31 xx10^(-5)m^(3)//s],[=12.62 xx10^(-4)m^(3)//s]:}(a) Calculate the flow rate of area at cecton by use of conservaton of mass principle{:[Q_(1)=Q_(2)+Q_(2)],[12.62 xx10^(-4)=(7.854 xx10^(-4))+Q_(3)],[Q_(3)=4.766 xx10^(-4)m^(3)//s]:}calculate the crross secton area of fach holp{:[A_(n)=(pi)/(4)dn^(2)],[=(pi)/(4)xx(10^(-3))^(2)],[=7.854 xx10^(-7)m^(2)]:}calculale total cross sectonal arrea ... See the full answer