What is the electric flux through the shaded plane(top surface)?
r=0.2
E=3N/c
45°
【General guidance】The answer provided below has been developed in a clear step by step manner.Step1/1Electric flux through a surface is given byϕ=EAcos⁡(θ) Where E = magnitude of electric field passing through surface = 3N/C A = surface area = \( \mathrm{π{R}^{{2}}={3.14}×{\left({0.2}\right)}^{{2}}{m}^{{2}}={0.125}{m}^{{2}}} \) θ  = angle between normal to surface and el ... See the full answer
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