What is the pH of a solution that consists of 0.50 M H2C6H6O6 (ascorbic acid) and 0.75 MNaHC6H6O6 (sodium ascorbate)? For ascorbic acid, Ka = 6.8 × 10–5.
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pka = 5 - log6. 8 = 4.167 using Henderson equation pH = pka + log(base/acid) = 4.167 + log0. 75/0.5    = 4.34 ...