Question When a three-cylinder, four-stroke cycle, SI engine, operating at \( 4000 \mathrm{RPM} \) is connected to an eddy current dynamometer. \( 70.4 \mathrm{~kW} \) of power is dissipated by the dynamometer. The engine has a total displacement vohlme of \( 2.4 \) liters and a mechanical efficiency of \( 82 \% \) at \( 4000 \mathrm{RPM} \). Example Problem 2-3 Because of heat and mechanical losses, the dynamomeref (actual power engine). 1. power lost to friction in engine (power recorde 2. brake mean effective pressure 3. engine torque at \( 4000 \mathrm{RPM} \) 4. engine specific volume

【General guidance】The answer provided below has been developed in a clear step by step manner.Step1/2ExplanationWe have four-stroke cycle, SI engine, operating at 4000rpm. \( \begin{align*} \mathrm{{P}_{{{\left.{d}{y}\right.}{n}{m}{o}{m}{e}{t}{e}{r}}}} &= \mathrm{{70.4}{k}{W}} \end{align*} \)engine has a total displacement volume , 2.4 l\( \begin{align*} \mathrm{{V}} &= \mathrm{{2.4}\times{10}^{{-{{3}}}}{m}^{{3}}} \end{align*} \)(1) -We need to determine power lost due to friction. Explanation:Please refer to solution in this step.Step2/2\( \begin{align*} \mathrm{\eta} &= \mathrm{\frac{{P}_{{{\left.{d}{y}\right.}{n}}}}{{{B}.{P}.}}} \end{align*} \)Break power, \( \begin{align*} \mathrm{{B}{P}} &= \mathrm{\frac{{{70.4}{k}{W}}}{{0.93}}={75.69}{k}{W}} \end{align*} \)Now calculate Indicated power, \( \begin{align*} \mathrm{\eta_{{{m}{e}{c}{h}}}} &= \mathrm{\frac{{{B}{P}}}{{{I}{P}}}} \end{align*} \)IP = Indicated Power\( \begin{align*} \mathrm{{0.82}} &= \mathrm{\frac{{75.69}}{{{I}{P}}}}\\[3pt]\mathrm{{I}{P}} &= \mathrm{{92.30}{k}{W}} \end{align*} \)HenceFriction loss can be determined, \( \begin{align*} \mathrm{{I}{P}} &= \mathrm{{B}{P}+{F}{P}} \end{align*} \)FP = Friction Power\( \begin{align*} \mathrm{{F}{P}} &= \mathrm{{92.30}-{75.69}}\\[3pt]\mathrm{{F}{P}} &= \ma ... See the full answer