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Given reaction and data:A+Brarr Products According to rate law, rate equation can be written as:" Rate "=k[A]^(m)[B]^(n)Where, k is rate constant, R is rate and [A],[B] are respective concentration of reactants.Using given data (table), substitute respective values of [A], [B] and Initial rate (in above rate equation (X)) we get following rate equations; Now use different sets of any 2 equations from above table. (Note: for easier calculations use those 2 equations which contains same value concentration of either [A] or [B])Divide equation 3 by 4 ;{:[(0.500)/(1.125)=(k[0.060]^(m)[0.044]^(n))/(k[0.060]^(m)[0.066]^(n))],[0.444=([0.044]^(n))/([0.066]^(n))],[0.444=(0.667)^(n)],[0.444=(0.667)^(n)]:}Take log and solve for value of n :{:[log(0.444)=log{( ... See the full answer