Deltas_("surr ")=0 for an adiabatic prowes since for adiabatic process, DeltaS_("univ ")⩾0 then Deltas_("sys ")+Deltas_("surn ")⩾0so, it is FALSEDelta S=0 for an adiabatic process since, Delta s=(Delta Q)/(T)If the process is adiabatic then Delta Q=0 so, Delta s=(0)/(T)=0quad:.Delta s=0TRUEDeltas_("univ ")=0 for a reversible processFor reversible process,DeltaS_("univ ")=DeltaS_("sys ... See the full answer