Which one of the following procedures would result in a buffer
with pH close to 9.0?
Ka(CH3COOH) = 1.8 × 10-5
Kb(NH3) = 1.8 × 10-5
Mixing 1 mol CH3COOH and 1 mol NH3 in a 1.0 L aqueous solution.
Mixing 1 mol CH3COOH and 1 mol NaOH in a 1.0 L aqueous solution.
Mixing 1 mol NH3 and 0.5 mol HCl in a 1.0 L aqueous solution.
Mixing 1 mol CH3COOH and 0.5 mol NaOH in a 1.0 L aqueous solution.
Mixing 1 mol NH3 and 1 mol HCl in a 1.0 L aqueous solution.
 Buffer is solution of weak acid and its conjugate base orWeak base and its conjugate acid.pH of buffer depends on Ka value.Ka of CH3COOH = 1.8*10-5 , pka =4.745Kb of NH3 = 1.8*10-5, pkb = 4.745 orpKa =  14 - 4.745 = 9.525 So,  1 mol NH3 and 0.5 mol HCl  in 1.0L aqueous solution  will form  buffer with pH close to9. calc ... See the full answer