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Solution: UDP header size = 8 bytes IP header size = 20 bytes MTU = 1500 bytes Data in 1 ethernet frame = MTU - ( UDP + IP header size ) = 1500 - 28 = 1472 bytes Total data size = 30,000,000 bytes Total number of IP packets = 30,000,000 / 1472 = 20381 packets  Total data sent = Total number of IP packets x (Total header + checksum bytes) + Data file size                           = 20381 x (20 + 8 + 14 + 4) + 30,000,000                           = 937,526 + 30,000,000                           = 30,937,527 bytes Answer : Total data sent is 30,937,527 bytes   Please thumbs up if you like the answer :) ...