You have an 8-inch pvc water main that is 2.0 miles long flowing at 650 gpm. Point A is at an elevation of 2,535 ft. Point B is at an elevation of 2,600 ft. If the pressure in a water main at Point A is 125 psi, what is the pressure at point B, in psi?

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Sef:r given data{:[{:[" length of pipe "=2" miles "=3.218km],[(L)]:}],[L=3218m],[d=8" inch "=0.2032m],[Q=650gpm=0.227 xx650m^(3)//hr],[=(0.227 xx650)/(60)m^(3)//s],[Q=2.46m^(3)//s]:}Elevation of point A=2535ft=772.67mElevation of point B=792.5mPressure in water main of point A,P_(A)=125psi{:[P_(A)=125 xx6.895kPa],[P_(A)=861.88kPa]:}Pressire at B,P_(B)= ?:. As Diameter of pipe is Same of beth points.V_(A)=V_(B)=Vhead loss in pipe h_(L)=(fLv^(2))/(2gD)Reynold's number Re=(rho vD)/(4)x_(1) is wot givenAssuming f low is laminar f=(c_(4))/(R_(e))R ... See the full answer