You have an 8-inch pvc water main that is 2.0 miles long flowing at 650 gpm. Point A is at an elevation of 2,535 ft. Point B is at an elevation of 2,600 ft. If the pressure in a water main at Point A is 125 psi, what is the pressure at point B, in psi?

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Ques Given data{:[" Length of pipe "L=2" miles "=1.6km],[L=1600m],[" Diametar of pipe "=8" inch "],[D=0.2032m],[" Discharge "Q=650gmm],[=0.227 xx650m^(3)//hr],[=(0.227 xx850)/(60)m3//s],[Q=2.46m^(3)//s]:}Elevation of peint A_(1)=2535ft=772.67mElevation of point B=792.5mpressure in water main at Point A,P_(A)=125 psi{:[P_(A)=125 xx6.895kPa],[P_(A)=861.88kPa]:}pressure at B,P_(B)= ?As diametar of pipe is same at both points, 50 velacity at point A will be equal too at peint BV_(B)=V_(A)=VHead luss in pipe h_(c)=(fLV^(2))/(2gD)Renold's number Re=(rho VD)/(mu) ( mu is not given)Assuming. flow is laminar f=( ... See the full answer